我想为我的设备创建一个StandBy活动,到目前为止,我创建了一个活动,在调用时将关闭我的显示.
代码如下：
public class MainActivity extends Activity {
private SensorManager mSensorManager;
private PowerManager mPowerManager;
private WindowManager mWindowManager;
private WakeLock mWakeLock;
private Button button;
private TextView textView;
/** Called when the activity is first created. */
@Override
public void onCreate(final Bundle savedInstanceState) {
super.onCreate(savedInstanceState);
try {
// Get an instance of the SensorManager
mSensorManager = (SensorManager) getSystemService(SENSOR_SERVICE);
// Get an instance of the PowerManager
mPowerManager = (PowerManager) getSystemService(POWER_SERVICE);
// Get an instance of the WindowManager
mWindowManager = (WindowManager) getSystemService(WINDOW_SERVICE);
mWindowManager.getDefaultDisplay();
setContentView(R.layout.activity_main);
// textView = (TextView)findViewById(R.id.textView1);
button = (Button) findViewById(R.id.testText);
button.setOnClickListener(mButtonStopListener);
mWakeLock = mPowerManager.newWakeLock(
PowerManager.PARTIAL_WAKE_LOCK,"Your Tag");
// mWakeLock.acquire();
final WindowManager.LayoutParams params = getWindow()
.getAttributes();
params.screenBrightness = 0;
getWindow().setAttributes(params);
} catch (final Exception e) {
// TODO Auto-generated catch block
e.printStackTrace();
Log.e("onCreate",e.getMessage());
}
} // END onCreate
View.OnClickListener mButtonStopListener = new OnClickListener() {
@Override
public void onClick(final View v) {
try {
if (mWakeLock.isHeld()) {
mWakeLock.release();
System.err.println("mWakeLock.release() onTouch");
}
} catch (final Exception e) {
// TODO Auto-generated catch block
e.printStackTrace();
Log.e("onPause",e.getMessage());
}
}
};
@Override
protected void onResume() {
super.onResume();
try {
if (mWakeLock.isHeld()) {
System.err.println("mWakeLock.release() onResume");
mWakeLock.release();
} else {
System.err.println("mWakeLock.acquire() onResume");
mWakeLock.acquire();
}
} catch (final Exception e) {
// TODO Auto-generated catch block
e.printStackTrace();
Log.e("onResume",e.getMessage());
}
}
@Override
protected void onPause() {
super.onPause();
}
}
正如我所说的这个代码使我能够关闭屏幕,我可以打开屏幕点击两次电源按钮(我不知道为什么我有两次点击按钮两次,但这是次要问题) .
主要问题是当显示器关闭时,生成ACTION_SCREEN_OFF动作,因此android EthernetService禁用我的连接.任何人都知道如何保持连接活动？
谢谢;)
解决方法
根据您的问题,我发现您需要保持以太网服务的活跃性.
首先,如果您在设备上有WiFi连接并且可以使用WiFi连接,则可以解决该问题.在这种情况下,您可以使用WifiLock和Partial WakeLock – see this question.
但是,如果您确实需要使用以太网连接,则可以尝试listening for ACTION_SCREEN_OFF intent,然后按照top reply to this question中的说明尝试重新启用以太网连接.请注意,在这种情况下,您的设备可能必须植根.
希望这可以帮助..
