我需要以String的形式访问复杂Json中包含的所有单个参数.
例如String people = …;
String idPeople = …;等等
我试图使用JSONTokeners,因为我试图搜索类似的问题,而对于简单的json,我没有问题,但我不知道如何从这里正确获取参数：
- {"id":1,"error":null,"result":
- {"nPeople":2,"people":[
- {"namePeople":"Inca","power":"1235","location":"asdfghjja","idPeople":189,"mainItems":"brownGem","verified":false,"description":"Lorem impsum bla bla","linkAvatar":"avatar_12.jpg","longitude":16.2434263,"latitude":89.355118},{"namePeople":"Maya","location":"hcjkjhljhl","idPeople":119,"mainItems":"greenstone","linkAvatar":"avatar_6.jpg","latitude":89.3551185}]
- }
- }
NB数组中对象的数量并不总是2 …并且可能包含4个或更多人对象
解决方法
我没试过.
但我想它可能会奏效.
但我想它可能会奏效.
- JSONObject obj = new JSONObject(jsonString);
- String id = obj.getString("id");
- String error = obj.getString("error");
- JSONObject result = obj.getJSONObject("result");
- int nPeople = result.getInt("nPeople");
- JSONArray people = result.getJSONArray("people");
- for(int i = 0 ; i < people.length() ; i++){
- JSONObject p = (JSONObject)people.get(i);
- String namePeople = p.getString("namePeople");
- ...
- }
