我试图通过参考这个链接：
https://github.com/jpotts18/android-mvp在我的Android项目中实现MVP模式
我已经成功实现了视图/演示者/交互者类.我不清楚
>哪里可以把服务电话代码？
Since i cannot get the context inside the presenter or interactor
class,I am not able to put theservicecall there
>在哪里实现GoogleApiClient类？
Since
GoogleApiClientalso requires context to run,it also cannot be
implemented inside the presenter or interactor without a context
解决方法
使用匕首可以更容易地在演示者上注入Interactor.尝试此链接(
https://github.com/spengilley/AndroidMVPService)
我试图实现它没有匕首.但这似乎违反了MVP架构.
从Activity开始,我创建了一个Interactor实例.然后使用Interactor创建Presenter的实例作为参数之一.
活动
public class SomeActivity extends Activity implements SomeView {
private SomePresenter presenter;
@Override
protected void onCreate(Bundle savedInstanceState) {
super.onCreate(savedInstanceState);
SomeInteractor interactor = new SomeInteractorImpl(SomeActivity.this);
presenter = new SomePresenterImpl(interactor,this);
}
@Override
protected void onStart() {
super.onStart();
presenter.startServiceFunction();
}
主持人
public interface SomePresenter {
public void startServiceFunction();
}
演示者实现
public class SomePresenterImpl implements SomePresenter {
private SomeInteractor interactor;
private SomeView view;
public SomePresenterImpl(SomeInteractor interactor,SomeView view){
this.interactor = interactor;
this.view = view;
}
@Override
public void startServiceFunction() {
interactor.startServiceFunction();
}
}
交互器
public interface SomeInteractor {
public void startServiceFunction();
}
互动实现
public class SomeInteractorImpl implements SomeInteractor {
private Context context;
public SomeInteractorImpl(Context context) {
this.context = context;
}
@Override
public void startServiceFunction() {
Intent intent = new Intent(context,SomeService.class);
context.startService(intent);
}
}
