我正在尝试创建一个自定义对话框来显示此对话框中的视图.这是Builder代码：
//Getting the layout
LayoutInflater inflater = (LayoutInflater) getSystemService(LAYOUT_INFLATER_SERVICE);
View layout = inflater.inflate(R.layout.custom_dialog_simple,(ViewGroup) findViewById(R.id.rlDialogSimple));
//Change Text and on click
TextView tvDialogSimple = (TextView) layout.findViewById(R.id.tvDialogSimple);
tvDialogSimple.setText(R.string.avisoComprobar);
Button btDialogSimple = (Button) layout.findViewById(R.id.btDialogSimple);
btDialogSimple.setOnClickListener(new OnClickListener() {
public void onClick(View v) {
//Do some stuff
//Here i want to close the dialog
}
});
AlertDialog.Builder builder = new AlertDialog.Builder(AcPanelEditor.this);
builder.setView(layout);
AlertDialog alert = builder.create();
alert.show();
所以,我想在btDialogSimple的onClick中关闭对话框.我该怎么办？我不知道如何从onclicklistener内调用dismiss方法.
我的按钮有一个自定义的布局,所以我不想做一个builder.setPositiveButton.
有任何想法吗？
解决方法
您必须将AlertDialog保存到您的父类属性中,然后使用以下内容：
class parentClass ........ {
private AlertDialog alert=null;
........
public void onClick(View v) {
//Do some stuff
//Here i want to close the dialog
if (parentClass.this.alert!=null)
parentClass.this.alert.dismiss();
}
........
this.alert = builder.create();
this.alert.show();
}
