我已经看到了如何实现BroadCastReceiver的几个例子,但是我应该如何实现必须对一些待处理的Intent(例如来电)做出反应的服务…
其实我是想知道同样的“问题”,但在一个活动..
你显然有一个扩展一个服务或活动的类),因此它不能扩展BroadCastReceiver …
看起来我们不能使“平台感知”服务和/或活动？
其实我是想知道同样的“问题”,但在一个活动..
你显然有一个扩展一个服务或活动的类),因此它不能扩展BroadCastReceiver …
看起来我们不能使“平台感知”服务和/或活动？
解决方法
要注册一个活动以获得某种意图,您需要：
// Flag if receiver is registered
private boolean mReceiversRegistered = false;
// I think this is the broadcast you need for something like an incoming call
private String INCOMING_CALL_ACTION = "android.intent.action.PHONE_STATE";
// Define a handler and a broadcast receiver
private final Handler mHandler = new Handler();
private final BroadcastReceiver mIntentReceiver = new BroadcastReceiver() {
@Override
public void onReceive(Context context,Intent intent) {
// Handle reciever
String mAction = intent.getAction();
if(mAction.equals(INCOMING_CALL_ACTION) {
// Do your thing
}
}
@Override
protected void onResume() {
super.onResume();
// Register Sync Recievers
IntentFilter intentToReceiveFilter = new IntentFilter();
intentToReceiveFilter.addAction(INCOMING_CALL_ACTION);
this.registerReceiver(mIntentReceiver,intentToReceiveFilter,null,mHandler);
mReceiversRegistered = true;
}
@Override
public void onPause() {
super.onPause();
// Make sure you unregister your receivers when you pause your activity
if(mReceiversRegistered) {
unregisterReceiver(mIntentReceiver);
mReceiversRegistered = false;
}
}
那么您还需要在清单中添加意图过滤器：
<activity android:name=".MyActivity" android:label="@string/name" >
<intent-filter>
<action android:name="android.intent.action.PHONE_STATE" />
</intent-filter>
</activity>
