我想在我正在开发的
Android应用程序上放置一个超链接.
我试过这个：
main.xml中
<TextView android:layout_width="fill_parent" android:layout_height="fill_parent" android:text="@string/hyperlink" android:id="@+id/hyperlink" android:autoLink="web" > </TextView>
strings.xml
<?xml version="1.0" encoding="utf-8"?> <resources> <string name="app_name">WebLink</string> <string name="hyperlink">http://google.com</string> </resources>
但问题是,链接看起来像这样：http://google.com,我不想显示实际网址.
1)如何通过“点击此处访问Google”等文本替换链接,文本是否与网站网址链接？
2)如何放置电子邮件地址(同样的问题,如何用“Click Here to Email”等文本替换它,文本应与email@domain.com链接)
我也试过这个教程：http://coderzheaven.com/2011/05/10/textview-with-link-in-android/
但我收到以下错误消息：
Description Resource Path Location Type http cannot be resolved to a variable MyLink.java /MyLink/src/com/MyLink line 21 Java Problem Syntax error on token "" <br /> <a href="",? expected after this token MyLink.java /MyLink/src/com/MyLink line 21 Java Problem Type mismatch: cannot convert from String to boolean MyLink.java /MyLink/src/com/MyLink line 20 Java Problem
解决方法
@H_502_27@ 使用默认值 Linkify class.public class StackOverflowActivity extends Activity {
@Override
public void onCreate(Bundle savedInstanceState) {
super.onCreate(savedInstanceState);
setContentView(R.layout.main);
// 1) How to replace link by text like "Click Here to visit Google" and
// the text is linked with the website url ?
TextView link = (TextView) findViewById(R.id.textView1);
String linkText = "Visit the <a href='https://stackoverflow.com'>StackOverflow</a> web page.";
link.setText(Html.fromHtml(linkText));
link.setMovementMethod(LinkMovementMethod.getInstance());
// 2) How to place email address
TextView email = (TextView) findViewById(R.id.textView2);
String emailText = "Send email: <a href=\"mailto:person@stackoverflow.com\">Click Me!</a>";
email.setText(Html.fromHtml(emailText));
email.setMovementMethod(LinkMovementMethod.getInstance());
}
}
