嗨,我可以使用此代码获取事件
cur = null;
cr = getContentResolver();
// Construct the query with the desired date range.
Uri.Builder builder = Instances.CONTENT_URI.buildUpon();
ContentUris.appendId(builder,0);
ContentUris.appendId(builder,endMillis);
// Submit the query
cur = cr.query(builder.build(),INSTANCE_PROJECTION,null,null);
但是如你所见,我只能在给定的持续时间内获得事件,但我需要所有事件(没有任何时间规范,不包括重复事件)这可能吗？如何 ？
请帮我.
cur = cr.query(Uri.parse("content://com.android.calendar/events"),null);
它给出了错误java.lang.IllegalArgumentException：
解决方法
试试这个代码……
public class Utility {
public static ArrayList<String> nameOfEvent = new ArrayList<String>();
public static ArrayList<String> startDates = new ArrayList<String>();
public static ArrayList<String> endDates = new ArrayList<String>();
public static ArrayList<String> descriptions = new ArrayList<String>();
public static ArrayList<String> readCalendarEvent(Context context) {
Cursor cursor = context.getContentResolver()
.query(
Uri.parse("content://com.android.calendar/events"),new String[] { "calendar_id","title","description","dtstart","dtend","eventLocation" },null);
cursor.moveToFirst();
// fetching calendars name
String CNames[] = new String[cursor.getCount()];
// fetching calendars id
nameOfEvent.clear();
startDates.clear();
endDates.clear();
descriptions.clear();
for (int i = 0; i < CNames.length; i++) {
nameOfEvent.add(cursor.getString(1));
startDates.add(getDate(Long.parseLong(cursor.getString(3))));
endDates.add(getDate(Long.parseLong(cursor.getString(4))));
descriptions.add(cursor.getString(2));
CNames[i] = cursor.getString(1);
cursor.moveToNext();
}
return nameOfEvent;
}
public static String getDate(long milliSeconds) {
SimpleDateFormat formatter = new SimpleDateFormat(
"dd/MM/yyyy hh:mm:ss a");
Calendar calendar = Calendar.getInstance();
calendar.setTimeInMillis(milliSeconds);
return formatter.format(calendar.getTime());
}
}
你也可以检查一下
