我在项目中遇到了问题.
我想使用“Google API”登录我的LoginActivity.并从另一个Activity(名为WelcomeActivity)注销
我想使用“Google API”登录我的LoginActivity.并从另一个Activity(名为WelcomeActivity)注销
public class LoginActivity extends AppCompatActivity implements
GoogleApiClient.OnConnectionFailedListener,View.OnClickListener {
// Configuration of Google API - Step 1/3
private static final String TAG = "LoginActivity";
private static final int RC_SIGN_IN = 9001;
public static GoogleApiClient mGoogleApiClient;
private ProgressDialog mProgressDialog;
@Override
protected void onCreate(Bundle savedInstanceState) {
super.onCreate(savedInstanceState);
GoogleAPI();
}
public void GoogleAPI(){
// Button listeners
findViewById(R.id.sign_in_button).setOnClickListener(this);
GoogleSignInOptions gso = new GoogleSignInOptions.Builder(GoogleSignInOptions.DEFAULT_SIGN_IN)
.requestEmail()
.build();
mGoogleApiClient = new GoogleApiClient.Builder(this)
.enableAutoManage(this /* FragmentActivity */,this /* OnConnectionFailedListener */)
.addApi(Auth.GOOGLE_SIGN_IN_API,gso)
.build();
}
@Override
public void onStart() {
super.onStart();
....
}
// [START onActivityResult]
@Override
public void onActivityResult(int requestCode,int resultCode,Intent data) {
super.onActivityResult(requestCode,resultCode,data);
// Result returned from launching the Intent from GoogleSignInApi.getSignInIntent(...);
if (requestCode == RC_SIGN_IN) {
GoogleSignInResult result = Auth.GoogleSignInApi.getSignInResultFromIntent(data);
handleSignInResult(result);
}
}
// [END onActivityResult]
// [START handleSignInResult]
private void handleSignInResult(GoogleSignInResult result) {
if (result.isSuccess()) {
// Signed in successfully,show authenticated UI.
CustomApplication app = (CustomApplication)getApplication();
GoogleSignInAccount acct = result.getSignInAccount();
Intent i = new Intent(LoginActivity.this,WelcomePage.class);
i.putExtra("Username",acct.getDisplayName());
startActivity(i);
}
}
// [END handleSignInResult]
// [START signIn]
private void signIn() {
Intent signInIntent = Auth.GoogleSignInApi.getSignInIntent(mGoogleApiClient);
startActivityForResult(signInIntent,RC_SIGN_IN);
}
// [END signIn]
@Override
public void onConnectionFailed(ConnectionResult connectionResult) {
...
}
private void showProgressDialog() {
...
}
private void hideProgressDialog() {
...
}
@Override
public void onClick(View v) {
switch (v.getId()) {
case R.id.sign_in_button:
signIn();
break;
….
}
}
}
我想在Welcome活动中使用Sign_out方法,
private void signOut() {
// Auth.GoogleSignInApi.signOut(mGoogleApiClient).setResultCallback(
// new ResultCallback<Status>() {
// @Override
// public void onResult(Status status) {
// // [START_EXCLUDE]
//// updateUI(false);
// // [END_EXCLUDE]
// }
// });
// }
>将mGoogleApiClient作为全局变量(扩展Application或Singleton),我试试,但失败了,在欢迎页面中,mGoogleApiClient不为空,但错误是：mGoogleApiClient尚未连接.
>我调用LoginActivity.getMGoogleApiClient(静态变量),但也失败了,同样的错误：mGoogleApiClient尚未连接.
解决方法
当您启用AutoManage时,googleApiClient将在onStart上连接并在onStop上断开连接,并由库自动处理.您可以在其他活动中注销用户,无论您的代码是从后端注销用户,除了不从谷歌退出.
伪代码：
private void logout(){ //your logout code in the log out activity setCurrentUser(null); }
在使用googleApiClient的活动中,您可以检查用户是否登录了googleApiClient的onConnected回调.如果当前用户未登录,请从Google注销该用户.
@Override
public void onConnected(Bundle connectionHint) {
if (getCurrentUser() == null){
signOut();
}
}
private void signOut() {
Auth.GoogleSignInApi.signOut(mGoogleApiClientPlus).setResultCallback(
new ResultCallback<Status>() {
@Override
public void onResult(Status status) {
//signed out.
}
});
}
如果您不使用enableAutoManage并且不断开onStop中的客户端(我不知道是否推荐它),您可以使用2种方法,但我不建议使用googleApiClient对象的静态字段.
