我正在尝试在我的应用程序中创建多个通知.为了唯一地识别每个通知,我给了它们唯一的identifierId.以下是我的代码：
private void updateNotification(int notificationId,int clockStatusID,CharSequence text) {
//notificationManager.cancel(notificationId);
// throws up an ongoing notification that the timer is running
Log.i("TIMERCOUNT","Notification id: " + notificationId);
Notification not = new Notification(clockStatusID,// the
// icon
// for
// the
// status
// bar
text,// the text to display in the ticker
System.currentTimeMillis() // the timestamp for the
// notification to appear
);
Intent intent = new Intent();
intent.putExtra("notificationID",notificationId);
intent.setAction("actionstring" + System.currentTimeMillis());
intent.setClassName("com.chander.time.android.activities","com.chander.time.android.activities.Tabs");
not.setLatestEventInfo(self,getText(R.string.timer_notification_title),getText(R.string.timer_on_notification_text),PendingIntent
.getActivity(this,intent,PendingIntent.FLAG_UPDATE_CURRENT));
not.flags += Notification.FLAG_ONGOING_EVENT;
not.flags += Notification.FLAG_NO_CLEAR;
notificationManager.notify(notificationId,not);
}
问题：
当选择通知时,Tabs活动称为传递意图.我想访问在Tabs中选择的通知的唯一notificationId.我试图intent.putExtra()来保存notifyId的意图.但是,对于多个通知,它覆盖了notificationId并返回最新的通知.我不明白为什么会发生这种情况,我如何避免这种覆盖notificationId.
谢谢,
钱德尔
