java – 在Android键盘中每两个键输出一个字符

我正在 Android中为阿姆哈拉语言设计一个自定义键盘,但以下内容适用于许多其他非英语语言.

两个或更多个键的组合转换为一个字符.所以,如果用户键入’S’,键盘将输出’ሰ’…如果它们用字母’A’后跟,’ሰ’替换为’ሳ’.

我设法得到一个解决方案,如下所示,通过查看光标前的字符并对其进行检查.不过,我想知道是否有更简单和更干净的解决方案成为可能.

public void onKey(int primaryCode,int[] keyCodes) {
    InputConnection ic = getCurrentInputConnection();
    HashMap<String,Integer> en_to_am = new HashMap<String,Integer>();
    CharSequence pChar = ic.getTextBeforeCursor(1,0);
    int outKey = 0;

    //build a hashmap of 'existing character' + 'new key code' = 'output key code'
    en_to_am.put("83",4656);
    en_to_am.put("ሰ65",4659);

    try {
        //see if config exists in hashmap for 'existing character' + 'new key code'
        if (en_to_am.get(pChar.toString() + primaryCode) != null) {
            outKey = en_to_am.get(pChar.toString() + primaryCode);
            ic.deleteSurroundingText(1,0);
        } else {
            //else just translate latin to amharic (ASCII 83 = ሰ)
            if (en_to_am.get("" + primaryCode) != null) {
                outKey = en_to_am.get("" + primaryCode);
            } else {
                //if no translation exists,just output the latin code
                outKey = primaryCode;
            }
        }
    } catch (Exception e) {
        outKey = primaryCode;
    }

    char code = (char) outKey;
    ic.commitText(String.valueOf(code),1);
}

解决方法

这里有一些改变,我建议使它更有效率

>使用自己的变量跟踪编辑状态.在下面的代码中,我使用mComposing,将其清除为onStartInput,并在新的输入时进行更新.
>减少使用String.我已经使用自定义类替换了字符串,重组了转换映射.
>使用撰写文字给用户更好的提示你在做什么.

这是修改后的代码

private StringBuilder mComposing = new StringBuilder();
private static HashMap<Integer,CodeInfo> mCodeMap = new HashMap<Integer,CodeInfo>();

private static class CodeInfo {
   final Character mCode;
   final Map<Character,Character> mCombinedCharMap;

   CodeInfo(Character code,Map<Character,Character> combinedCharMap) {
       mCode = code;
       mCombinedCharMap = combinedCharMap;
   }
}

static {
    //reminder,do not input combinedCharMap as null

    mCodeMap.put(83,new CodeInfo(Character.valueOf((char)4656),new HashMap<Character,Character>());
    HashMap<Character,Character> combinedCharMap = new HashMap<Character,Character>();
    combinedCharMap.put(Character.valueOf('ሰ'),Character.valueOf((char)4659))
    mCodeMap.put(65,new CodeInfo(null,combinedCharMap);
}

@Override 
public void onStartInput(EditorInfo attribute,boolean restarting) {
    super.onStartInput(attribute,restarting);
    mComposing.setLength(0);


    //other codes you already have
}       

public void onKey(int primaryCode,int[] keyCodes) {
    InputConnection ic = getCurrentInputConnection();

    CodeInfo codeInfo = mCodeMap.get(primaryCode);
    Character output = null;
    if (codeInfo != null) {
        if (mComposing.length() > 0) {
            Character combinedOutput = codeInfo.mCombinedCharMap.get(mComposing.charAt(0));
            if (combinedOutput != null) {
                //the length is mComposing is expected to be 1 here
                mComposing.setCharAt(0,combinedOutput);
                ic.finishComposingText();
                ic.setComposingText(mComposing,1);
                return;
            }
        }
        output = codeInfo.mCode;        
    }
    if (mComposing.length() > 0) {
       mComposing.setLength(0);
       ic.finishComposingText();
    }
    mComposing.append(output==null?(char)primaryCode:(char)output);
    ic.setComposingText(mComposing,1);
}

原文链接：https://www.f2er.com/android/123673.html

java – 在Android键盘中每两个键输出一个字符

解决方法

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