<html>
<head>
<script language="JavaScript" type="text/javascript" src="js/jquery.js"></script>
<script language="JavaScript" type="text/javascript" src="js/jquery.timer.js"></script>
<script type="text/JavaScript">
$(document).ready(function(){
$('#submitbt').click(function(){
//var name = $('#name').val();
//var dataString = "name="+name;
var dataPass = {
'name': $("#name").val()
};
$.ajax({
type: "POST",url: "post.PHP",//data: dataString,字符串传值方式
data: dataPass,//json传值方式
success: function (data) {
alert(data);
var re = $.parseJSON(data || "null");
console.log(re);
}
});
});
});
</script>
</head>
<body>
<form id="form" name="form" id="myform" method="post">
<label>Name</label>
<input name="name" type="text" id="name" />
<input type="button" class="button" id="submitbt" value="submit" >
</form>
</body>
</html>
<?PHP $name = $_POST['name']; echo json_encode(array('name'=>$name));//为什么return就不行呢？ ?>
参考：检测json格式： http://jsonlint.com/
