@*公共的razor帮助方法*@
@*郑凯 2014-3-28*@
@using System.Web.Mvc;
@helper AjaxActionLink_ToOtherSys(System.Web.Mvc.AjaxHelper helper,string dispName,int requestType) { //直接写@Ajax.ActionLink不行 WebViewPage currentWebViewPage = CurrentPage as WebViewPage; System.Web.Mvc.Ajax.AjaxExtensions.ActionLink(currentWebViewPage.Ajax,dispName,"ToOtherSys","Home",new { RequestType = requestType },new System.Web.Mvc.Ajax.AjaxOptions { HttpMethod = "Post",OnSuccess = "AlertMsg",OnFailure = "AlertError" }); }
原文链接:https://www.f2er.com/ajax/165092.html