Ajax入门学习

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Ajax主要来实现局部刷新的。

这是一个项目:

AjaxTest.java(Servlet)

import javax.servlet.ServletException;
import javax.servlet.http.HttpServlet;
import javax.servlet.http.HttpServletRequest;
import javax.servlet.http.HttpServletResponse;
import java.io.IOException;
import java.io.PrintWriter;

/**
 * Created by Administrator on 2016/12/1.
 */
public class AjaxTest extends HttpServlet {

    @Override
    public void doGet(HttpServletRequest req,HttpServletResponse resp) throws ServletException,IOException {
        PrintWriter out = resp.getWriter();
       String name= req.getParameter("name");
       if(name==null||name.equals(""))
       {
            out.println("please input username");
       } else if(name.equals("wh")){
           out.println("welcome "+name);
       }else{
            out.println("the user doesn't esist!");
       }
    }


    @Override
    public  void doPost(HttpServletRequest req,IOException {
     doGet(req,resp);
    }
}
ajax.html(填写数据,展示页面)
<!DOCTYPE html>
<html lang="en">
<head>
    <Meta charset="UTF-8">
    <title>Title</title>
    <script  type="text/javascript" src="jquery-3.1.1.js"></script>
    <script  type="text/javascript" src="verify.js"></script>
</head>
<body>
使用ajax技术处理
<input type=text" id="input" name="name" />
<input type="button" value="校验" onclick="verify()"/>
<div id="result"></div>

</body>
</html>
verify.js
function  verify() {
    var input = $("#input");
    var username = input.val();
    $.get("AjaxTest?name="+username,null,callback);
}
function callback(data){
    var res=$("#result");
    res.html(data);
}
每点击一下按钮,就会调用verify函数,从Servlet调出数据,显示在div里。

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