我的网站上有一个民意调查,每个答案旁边都会显示单选按钮.当用户选择一个选项并提交时,我通过ajax运行一个PHP脚本,将值或选中的单选按钮插入表中.
我的Ajax正在运行但是当前每行都插入一行0,所以它没有从单选按钮中获取值.任何帮助,将不胜感激.
HTML:
<form id="poll_form" method="post" accept-charset="utf-8"> <input type="radio" name="poll_option" value="1" id="poll_option" /><label for='1'> Arts</label><br /> <input type="radio" name="poll_option" value="2" id="poll_option" /><label for='2'> Film</label><br /> <input type="radio" name="poll_option" value="3" id="poll_option" /><label for='3'> Games</label><br /> <input type="radio" name="poll_option" value="4" id="poll_option" /><label for='4'> Music</label><br /> <input type="radio" name="poll_option" value="5" id="poll_option" /><label for='5'> Sports</label><br /> <input type="radio" name="poll_option" value="6" id="poll_option" /><label for='6'> Television</label><br /> <input type="submit" value="Vote →" id="submit_vote" class="poll_btn"/> </form>
AJAX:
$("#submit_vote").click(function(e) { var option=$('input[type="radio"]:checked').val(); $optionID = "="+optionID; $.ajax({ type: "POST",url: "ajax_submit_vote.PHP",data: {"optionID" : $optionID} }); });
PHP :(缩短版)
if($_SERVER['REQUEST_METHOD'] == "POST"){ //Get value from posted form $option = $_POST['poll_option']; //Insert into db $insert_vote = "INSERT into poll (userip,categoryid) VALUES ('$ip','$option')";
提前致谢!
$("#submit_vote").click(function(e){ $.ajax( { type: "POST",data: $('#poll_form').serialize(),success: function( response ) {} }); });
然后,您应该在PHP脚本中访问POST变量“poll_option”.