我正在Catalyst中构建一个数据库应用程序,使用jqGrid来完成处理数据显示的混乱工作.除了能够通过“标签”过滤搜索结果外,我几乎所有工作都有效.我有三个表,关系如下:
package MyApp::Schema::Result::Project; ... __PACKAGE__->has_many( "job_flags","MyApp::Schema::Result::ProjectFlag",{ "foreign.project_id" => "self.id" },{ cascade_copy => 0,cascade_delete => 0 },); ... __PACKAGE__->many_to_many(flags => 'project_flags','flag'); 1;
和
package MyApp::Schema::Result::Flag; ... __PACKAGE__->has_many( "project_flags",{ "foreign.flag_id" => "self.id" },); ... __PACKAGE__->many_to_many(projects => 'project_flags','project'); 1;
最后,连接表
package MyApp::Schema::Result::ProjectFlag; ... __PACKAGE__->belongs_to( "flag","MyApp::Schema::Result::Flag",{ id => "flag_id" },{ is_deferrable => 1,on_delete => "CASCADE",on_update => "CASCADE" },); ... __PACKAGE__->belongs_to( "project","MyApp::Schema::Result::Project",{ id => "project_id" },); ... 1;
在我向jqGrid提供JSON数据的控制器中,我使用Catalyst :: TraitFor :: Controller :: jQuery :: jqGrid :: Search将jqGrid生成的请求参数转换为DBIx :: Class样式的查询:
my $search_filter = $self->jqGrid_search($c->req->params); my $project_rs = $c->model('DB::Project')->search( $search_filter,{ join => 'project_flags',group_by => 'id',},);
$project_rs = $self->jqgrid_page($c,$project_rs);
然后我迭代结果集并构建我的jqGrid列.
在HTML方面,我能够构建一个类似的JSON字符串
{"groupOp":"AND","rules":[{"field":"project_flags.flag_id","op":"eq","data":"2"}]}
在这种情况下,显示项目在project_flags中有一行,标志ID为2.
我完全知道我没有正确地做到这一点!我在Catalyst和DBIx :: Class上可以找到的所有文档都表现出类似的想法,但我无法理解如何将它们应用于这种情况(不是我没有尝试过).
>我将如何构建“has_flag($flag_id)” – 类型访问器,然后能够在jqGrid的API中使用它们?在我的Catalyst应用程序中它属于哪里?
>我想过滤的方法之一是缺少特定的标志.
解决方法
我必须对你诚实,我不完全确定我理解你的问题.看起来你要问的是DBIx :: Class比Catalyst更多 – 后者我知之甚少,前者我每天都在学习更多.考虑到这一点,这是我回答你的问题的最佳尝试.我使用MojolicIoUs作为MVC,因为这是我最了解的.
首先,我首先创建一个多对多数据库:
CREATE TABLE project( id INTEGER PRIMARY KEY,name text ); CREATE TABLE flag( id INTEGER PRIMARY KEY,name text ); CREATE TABLE project_flag( project_id integer not null,flag_id integer not null,FOREIGN KEY(project_id) REFERENCES project(id),FOREIGN KEY(flag_id) REFERENCES flag(id) ); INSERT INTO project (id,name) VALUES (1,'project1'); INSERT INTO project (id,name) VALUES (2,'project2'); INSERT INTO project (id,name) VALUES (3,'project3'); INSERT INTO flag (id,'flag1'); INSERT INTO flag (id,'flag2'); INSERT INTO flag (id,'flag3'); INSERT INTO flag (id,name) VALUES (4,'flag4'); INSERT INTO project_flag (project_id,flag_id) VALUES (1,1); INSERT INTO project_flag (project_id,2); INSERT INTO project_flag (project_id,3); INSERT INTO project_flag (project_id,4); INSERT INTO project_flag (project_id,flag_id) VALUES (2,4);
#!/usr/bin/env perl use MojolicIoUs::Lite; use Schema; helper db => sub { return Schema->connect('dbi:sqlite:test.db'); }; get '/' => sub { my $self = shift; my $rs = $self->db->resultset('Project')->search( { 'me.name' => 'project3' },{ join => { 'project_flags' => 'flag' },select => ['me.name','flag.name'],as => ['project','flag'] } ); $rs->result_class('DBIx::Class::ResultClass::HashRefInflator'); $self->render( json => [ $rs->all ] ); }; app->start;
这是来自project1的JSON输出(漂亮的打印)(有与之相关的标志):
[ { "project":"project1","flag":"flag1" },{ "flag":"flag2","project":"project1" },{ "project":"project1","flag":"flag3" },{ "flag":"flag4","project":"project1" } ]
这里是project3的JSON,与任何标志都没有关系:
[ { "project":"project3","flag":null } ]
我把文件放在Github上,所以如果你愿意的话可以check them out.
在你给定的情况下,假设他们在过滤器中输入了“c”这个词,你想要返回标记为“c”的所有内容,然后:
my $rs = $self->db->resultset('Tag')->search( { 'me.name' => 'c++' },{ join => { 'project_flags' => 'project' },'project.name'],as => ['tag','project'] } ); $rs->result_class('DBIx::Class::ResultClass::HashRefInflator'); $self->render( json => [ $rs->all ] );
如果要返回所有列,请使用prefetch而不是join.此外,如果您想支持自动搜索功能,请将搜索更改为search_like,如下所示:
my $rs = $self->db->resultset('Tag')->search_like( { 'me.name' => $search_filter.'%' },
我希望如果我没有回答你的问题,我所提出的至少是朝着正确的方向发展.