我想使用Class生成一个json行,我会覆盖gist方法,以便它打印出我想要的内容：
@H_502_28@解决方法
my $ak = '7111ac873c9dcd5fc335ded47630d050';
my $st = '1523451601875';
my $ifo = 'true';
my $uu = "15778787898988090";
class Stay {
has $.ak is rw = '7111ac873c9dcd5fc335ded47630d050';
has $.uu is rw;
has $.ifo is rw;
has $.st is rw;
method gist() {
#return qqww/{"ev":"app","ak":"$!ak","uu":"$!uu","ifo":"$!ifo","st":"$!st"}/;
return qqww:to「EOF」;
{"ev":"app","st":"$!st"}
EOF
}
}
say Stay.new(uu => $uu,ifo => $ifo,st => $st);
但失败了：
===SORRY!=== Error while compiling /Users/ohmycloud/Desktop/stay.pl6
Confused
at /Users/ohmycloud/Desktop/stay.pl6:18
------> {"ev":⏏"app","ifo":"$!i
expecting any of:
colon pair
我想要的是：
{"ev":"app","ak":"7111ac873c9dcd5fc335ded47630d050","uu":"15778787898988090","ifo":"true","st":"1523451601875"}
为什么我不能在qqww或qq中使用冒号对：结构？
你可以使用
unquoting：
method gist() {
return '{"ev":"app","ak":"\qq[$!ak]","uu":"\qq[$!uu]","ifo":"\qq[$!ifo]","st":"\qq[$!st]"}':
}
将返回
{"ev":"app","st":"1523451601875"}
如果你使用qqww或类似的话,冒号会妨碍你.