我正在尝试用
Bash脚本完成一项工作.我有一个字符串,我想用我的密钥进行异或.
#!/bin/sh PATH=/bin:/usr/bin:/sbin:/usr/sbin export PATH teststring="abcdefghijklmnopqr"
现在我如何XOR testtring的值并使用bash将其存储在变量中？
任何帮助将不胜感激.
基本上我试图复制以下VB脚本的结果：
Function XOREncryption(CodeKey,DataIn)
Dim lonDataPtr
Dim strDataOut
Dim temp
Dim tempstring
Dim intXOrValue1
Dim intXOrValue2
For lonDataPtr = 1 To Len(DataIn) Step 1
'The first value to be XOr-ed comes from the data to be encrypted
intXOrValue1 = Asc(Mid(DataIn,lonDataPtr,1))
'The second value comes from the code key
intXOrValue2 = Asc(Mid(CodeKey,((lonDataPtr Mod Len(CodeKey)) + 1),1))
temp = (intXOrValue1 Xor intXOrValue2)
tempstring = Hex(temp)
If Len(tempstring) = 1 Then tempstring = "0" & tempstring
strDataOut = strDataOut + tempstring
Next
XOREncryption = strDataOut
End Function
解决方法
在
these hints的帮助下,我写了这个快速的脚本来完成Pedro的答案：
#!/bin/bash
function ascii2dec
{
RES=""
for i in `echo $1 | sed "s/./& /g"`
do
RES="$RES `printf \"%d\" \"'$i\"`"
done
echo $RES
}
function dec2ascii
{
RES=""
for i in $*
do
RES="$RES`printf \\\\$(printf '%03o' $i)`"
done
echo $RES
}
function xor
{
KEY=$1
shift
RES=""
for i in $*
do
RES="$RES $(($i ^$KEY))"
done
echo $RES
}
KEY=127
TESTSTRING="abcdefghijklmnopqr"
echo "Original String: $TESTSTRING"
STR_DATA=`ascii2dec "$TESTSTRING"`
echo "Original String Data: $STR_DATA"
XORED_DATA=`xor $KEY $STR_DATA`
echo "XOR-ed Data: $XORED_DATA"
RESTORED_DATA=`xor $KEY $XORED_DATA`
echo "Restored Data: $RESTORED_DATA"
RESTORED_STR=`dec2ascii $RESTORED_DATA`
echo "Restored String: $RESTORED_STR"
结果：
iMac:Desktop fer$bash test.sh Original String: abcdefghijklmnopqr Original String Data: 97 98 99 100 101 102 103 104 105 106 107 108 109 110 111 112 113 114 XOR-ed Data: 30 29 28 27 26 25 24 23 22 21 20 19 18 17 16 15 14 13 Restored Data: 97 98 99 100 101 102 103 104 105 106 107 108 109 110 111 112 113 114 Restored String: abcdefghijklmnopqr