我有这个脚本加密密码,但我不知道如何扭转它并解密.这可能是一个非常简单的答案,但我不明白如何做到这一点.
#!/usr/bin/perl use Crypt::Eksblowfish::Bcrypt; use Crypt::Random; $password = 'bigtest'; $encrypted = encrypt_password($password); print "$password is encrypted as $encrypted\n"; print "Yes the password is $password\n" if check_password($password,$encrypted); print "No the password is not smalltest\n" if !check_password('smalltest',$encrypted); # Encrypt a password sub encrypt_password { my $password = shift; # Generate a salt if one is not passed my $salt = shift || salt(); # Set the cost to 8 and append a NUL my $settings = '$2a$08$'.$salt; # Encrypt it return Crypt::Eksblowfish::Bcrypt::bcrypt($password,$settings); } # Check if the passwords match sub check_password { my ($plain_password,$hashed_password) = @_; # Regex to extract the salt if ($hashed_password =~ m!^\$2a\$\d{2}\$([A-Za-z0-9+\\.]{22})!) { return encrypt_password($plain_password,$1) eq $hashed_password; } else { return 0; } } # Return a random salt sub salt { return Crypt::Eksblowfish::Bcrypt::en_base64(Crypt::Random::makerandom_octet(Length=>16)); }@H_403_3@