您是否想知道将“从您的历史中清除18岁以上”与“从您的历史中清除18岁以上？”相匹配的最佳方法是什么？使用Python。

我已经尝试过了

keyword = "clear 18+ from your history"
prepped_string = "clear 18+ from your history? blah blah blah"

is_flagged = False
if re.search(r'\b' + keyword + r'\b',prepped_string):
     is_flagged = True

以上代码仅适用于无特殊字符的情况。如果有特殊字符（如加号），则将无法使用。预先感谢。

这是完整的代码：

def _get_user_blacklist_weights(self,prepped_string,user):
        """
        Returns a list of (word,weight,reason) for every user word that is found.
        """
        out = []
        if user.blacklist:          
            matches = user.blacklist.search(prepped_string)
            for match in matches:
                is_flagged = False
                try:
                    if re.search(r'\b' + keyword + r'\b',prepped_string):
                        is_flagged = True
                except Exception as e:
                    # The condition below fixes both python 3.4 and 3.6 error message on repeating characters.
                    if (str(e)).startswith(C.REPEAT_ERROR_MESSAGES):
                        is_flagged = True
                    else: # pragma: no cover
                        error_logging(e)

                if is_flagged:
                    out.append((match,C.USER_BLACklist_MATCH_WEIGHT,'%s or one of his/her accountability partners asked that "%s" be flagged.' % (user.person.first_name.title(),match)))               
        return out